Question

(x+20)^100+gía trị tuyệt đối y+4=0,tìm x

Answer 1

\(\left(x+20\right)^{100}+\left|y+4\right|=0\)

mà \(\left(x+20\right)^{100}\ge0\forall x;\left|y+4\right|\ge0\forall y\)

Dấu "=" xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}x=-20\\y=-4\end{matrix}\right.\)

Answer 2

`(x+20)^100 + |y+4| =0`

ta có : `(x+2)^100 >= 0AAx`

`|y+4| >=0AAx`

`=>(x+20)^100 + |y+4| >=0 AA (x;y)`

Dấu ''='' xayra khi `{(x+20=0),(y+4=0):}`

`=> {(x=-20),(y=-4):}`

Vậy `{(x=-20),(y=-4):}` thì `(x+20)^100 + |y+4| =0`

Answer 3

thank