\(\dfrac{x^2+7x+10}{x+2}\)
\(=\dfrac{x^2+2x+5x+10}{x+2}\)
\(=\dfrac{x\left(x+2\right)+5\left(x+2\right)}{x+2}\)
=x+5
Ta có: \(x^2+7x+10\)
\(=x^2+2x+5x+10\)
\(=x\left(x+2\right)+5\left(x+2\right)\)
\(=\left(x+2\right)\left(x+5\right)\)
\(\Rightarrow\left(x^2+7x+10\right):\left(x+2\right)=x+5\)