Question

x^2-4xy+4y^2+xz-2yz

Answer 1

\(x^2-4xy+4y^2+xz-2yz\)

\(=\left(x^2-4xy+4y^2\right)+\left(xz-2yz\right)\)

\(=\left(x-2y\right)^2+z\left(x-2y\right)=\left(x-2y\right)\left(x-2y+z\right)\)

Answer 2

$#flo$

`x^2 - 4xy + 4y^2 + xz - 2yz`

`= [x^2 -4xy + (2y)^2] + z(x - 2y)`

`= (x-2y)^2 + z(x - 2y)`

`=(x-2y)(x-2y + z)`