-x2+2x-4=-(x2-2x+1)-3
=-(x-1)2<0 với mọi x =>-(x-1)2-3<0 với mọi x
Ta có : -x2 + 2x - 4 = -( x2 - 2x + 1 ) - 3
= -( x - 1 )2 - 3 ≤ -3 < 0 ∀ x
=> đpcm
\(-x^2+2x-4=-x^2+2x-1-3\)
\(=-\left(x^2-2x+1\right)-3=-\left(x-1\right)^2-3\)
Vì \(\left(x-1\right)^2\ge0\forall x\)
\(\Rightarrow-\left(x-1\right)^2\le0\forall x\)
\(\Rightarrow-\left(x-1\right)^2-3\le-3\forall x\)
hay \(-x^2+2x-4\le-3\)
\(\Rightarrow-x^2+2x-4< 0\forall x\)( đpcm )