Question

(x^2-16).(x+3)=0

Answer 1

\(\left(x^2-16\right)\left(x+3\right)=0\\ \Rightarrow\left(x-4\right)\left(x+4\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-4=0\\x+4=0\\x+3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=4\\x=-4\\x=-3\end{matrix}\right.\)

Answer 2

\(x\in\left\{-3,16\right\}\)

Answer 3

\(\Leftrightarrow\left(x-4\right).\left(x+4\right).\left(x+3\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-4=0\\x+4=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\x=-4\\x=-3\end{matrix}\right.\)

Vậy \(x\in\left\{4;-4;-3\right\}\)

Answer 4

nhầm xíu 

\(x\in\left\{-3,4,-4\right\}\)

Answer 5

(x2−16)(x+3)=0⇒(x−4)(x+4)(x+3)=0⇒⎡⎢⎣x−4=0x+4=0x+3=0⇒⎡⎢⎣x=4x=−4x=−3