\(\left(x^2-10\right):5=3\\ =>x^2-10=3\cdot5\\ =>x^2-10=15\\ =>x^2=10+15\\ =>x^2=25\\ =>x^2=5^2\\ =>x=\pm5\)
Vậy: ...
`x^2 - 10 = 3 xx 5`
`x^2 - 10 = 15`
`x^2 = 15 + 10 = 25`
`x^2 = + - 5^2`
`***)` TH1: `x^2 = (-5)^2`
`=> x = -5`
`***)` TH2: `x^2 = 5^2`
`=> x = 5`
\(\left(x^2-10\right):5=3\)
\(x^2-10=3\times5\)
\(x^2-10=15\)
\(x^2=15+10\)
\(x^2=25\)
\(x^2=5^2\)
\(x=5\)
Vậy x=5