`2 : x = x : 8/49`
`<=> x^2 = 16/49`
`<=> x = +-4/7`
Đúng 2
Bình luận (1)
Các câu hỏi tương tự
a) 2dfrac{1}{2} - x + dfrac{4}{5} dfrac{2}{3} - (-dfrac{4}{7} )
b) -dfrac{4}{7} - x dfrac{3}{5} - 2x
c) (dfrac{3}{8} - dfrac{1}{5} ) + (dfrac{5}{8} - x) dfrac{1}{5}
Đọc tiếp
a) \(2\dfrac{1}{2}\) - x + \(\dfrac{4}{5}\) = \(\dfrac{2}{3}\) - (\(-\dfrac{4}{7}\) )
b) \(-\dfrac{4}{7}\) - x = \(\dfrac{3}{5}\) - 2x
c) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\) ) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
Tìm x:a) 1dfrac{3}{4} . x + 1dfrac{1}{2} dfrac{-4}{5}b) x ( dfrac{1}{5} + dfrac{1}{4} ) - ( dfrac{1}{7} + dfrac{1}{8} ) 0c) | x | 3,5d) | x | -2,7e) | 1 - x | + 0,73 3f) 52 . 73 . 11x + 52 . 72 .11 0g) (3 . 5 + 5 . 7)x + ( 3 . 5 + 5 . 7) + (3 . 5 + 5 . 7) 0h) 52 . 72 . 112x - 52 . 72 . 114 0l) | x + dfrac{3}{4} | - 5 -2
Đọc tiếp
Tìm x:
a) \(1\dfrac{3}{4}\) . x + \(1\dfrac{1}{2}\) = = \(\dfrac{-4}{5}\)
b) x ( \(\dfrac{1}{5}\) + \(\dfrac{1}{4}\) ) - ( \(\dfrac{1}{7}\) + \(\dfrac{1}{8}\) ) = 0
c) \(|\) x \(|\) = 3,5
d) \(|\) x \(|\) = -2,7
e) \(|\) 1 - x \(|\) + 0,73 = 3
f) 52 . 73 . 11x + 52 . 72 .11 = 0
g) (3 . 5 + 5 . 7)x + ( 3 . 5 + 5 . 7) + (3 . 5 + 5 . 7) = 0
h) 52 . 72 . 112x - 52 . 72 . 114 = 0
l) \(|\) x + \(\dfrac{3}{4}\) \(|\) - 5 = -2
Tìm x, biết:
a) dfrac{1}{20} - (x - dfrac{8}{5}) dfrac{1}{10}
b) dfrac{7}{4} - (x + dfrac{5}{3}) dfrac{-12}{5}
c) x - [dfrac{17}{2} - left(dfrac{-3}{7}+dfrac{5}{3}right)] dfrac{-1}{3}
Đọc tiếp
Tìm x, biết:
a) \(\dfrac{1}{20}\) - (x - \(\dfrac{8}{5}\)) = \(\dfrac{1}{10}\)
b) \(\dfrac{7}{4}\) - (x + \(\dfrac{5}{3}\)) = \(\dfrac{-12}{5}\)
c) x - [\(\dfrac{17}{2}\) - \(\left(\dfrac{-3}{7}+\dfrac{5}{3}\right)\)] = \(\dfrac{-1}{3}\)
1,dfrac{3}{16}- ( x - dfrac{5}{4} ) - ( dfrac{3}{4} + dfrac{-7}{8} - 1 ) 2dfrac{1}{2}
2,dfrac{1}{2} . ( dfrac{1}{6} - dfrac{9}{10} ) dfrac{1}{5} - x + ( dfrac{1}{15} - dfrac{-1}{5} )
Giúp mik nhanh với ạ .
Đọc tiếp
1,\(\dfrac{3}{16}\)- ( x - \(\dfrac{5}{4}\) ) - ( \(\dfrac{3}{4}\) + \(\dfrac{-7}{8}\) - 1 ) = \(2\dfrac{1}{2}\)
2,\(\dfrac{1}{2}\) . ( \(\dfrac{1}{6}\) - \(\dfrac{9}{10}\) ) = \(\dfrac{1}{5}\) - x + ( \(\dfrac{1}{15}\) - \(\dfrac{-1}{5}\) )
Giúp mik nhanh với ạ .
Tìm x:
a) \(-\dfrac{4}{7}\) - x = \(\dfrac{3}{5}\) - 2x
b) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\)) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
17 tháng 12 2021 lúc 19:49
a)x-\(\dfrac{2}{3}=\dfrac{8}{7}\)
b)\(\left(x+\dfrac{1}{3}\right)=\dfrac{4}{25}\)
c)\(-\dfrac{2}{3}\div x+\dfrac{5}{8}=-\dfrac{7}{12}\)
Tìm x, biết:
a) dfrac{-1}{10} + dfrac{2}{5}x + dfrac{7}{20} dfrac{1}{10}
b) dfrac{1}{3} + dfrac{1}{2} : x -dfrac{1}{5}
c) -dfrac{2}{3} : x + dfrac{5}{8} -dfrac{7}{12}
Đọc tiếp
Tìm x, biết:
a) \(\dfrac{-1}{10}\) + \(\dfrac{2}{5}\)x + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
b) \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) : x= \(-\dfrac{1}{5}\)
c) \(-\dfrac{2}{3}\) : x + \(\dfrac{5}{8}\) = \(-\dfrac{7}{12}\)
25 tháng 10 2021 lúc 19:47
1/Thực hiện phép tính:𝒂) ( dfrac{7}{5} − dfrac{8}{7} ) + 3dfrac{2}{5} ∶ 𝟎,𝟔b) dfrac{11}{6} + dfrac{7}{6} ∶ dfrac{-5}{4}c) dfrac{7}{4} − dfrac{5}{4} . dfrac{8}{15}2/ Tìm x biếtb) 𝒙 + 𝟐,𝟓 dfrac{-8}{3}b) 𝟐𝒙 − 𝟐𝟎% dfrac{9}{5}𝒄) ( dfrac{5}{4} )2 + 𝒙 2dfrac{3}{4}
Đọc tiếp
1/Thực hiện phép tính:
𝒂) ( \(\dfrac{7}{5}\) − \(\dfrac{8}{7}\) ) + \(3\dfrac{2}{5}\) ∶ 𝟎,𝟔
b) \(\dfrac{11}{6}\) + \(\dfrac{7}{6}\) ∶ \(\dfrac{-5}{4}\)
c) \(\dfrac{7}{4}\) − \(\dfrac{5}{4}\) . \(\dfrac{8}{15}\)
2/ Tìm x biết
b) 𝒙 + 𝟐,𝟓 = \(\dfrac{-8}{3}\)
b) 𝟐𝒙 − 𝟐𝟎% = \(\dfrac{9}{5}\)
𝒄) ( \(\dfrac{5}{4}\) )2 + 𝒙 = \(2\dfrac{3}{4}\)
Tìm x a,3-xx+1,8b,2x-57x+35c,2left(x+10right)3left(x-6right)d,8left(x-dfrac{3}{8}right)+16left(dfrac{1}{6}+xright)+xe,dfrac{2}{9}-3xdfrac{4}{3}-xg,dfrac{1}{2}x+dfrac{5}{6}dfrac{3}{4}x-dfrac{1}{2}h,x-4dfrac{5}{6}left(6-dfrac{6}{5}xright)k,7x^2-116x^2-2m,5left(x+3.2^3right)10^2n,dfrac{4}{9}-(dfrac{1}{6^2})dfrac{2}{3}left(x-dfrac{2}{3}right)^2+dfrac{5}{12}
Đọc tiếp
Tìm x
\(a,3-x=x+1,8\)
\(b,2x-5=7x+35\)
\(c,2\left(x+10\right)=3\left(x-6\right)\)
\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)
\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)
\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)
\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)
\(k,7x^2-11=6x^2-2\)
\(m,5\left(x+3.2^3\right)=10^2\)
\(n,\dfrac{4}{9}-(\dfrac{1}{6^2})=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)