Question

x mũ 2 cộng 2x cộng 1 trừ y mũ 2

phân tích nhóm hạng tử

Answer 1

x^2+2x+1−y^2

(a+b)^2=a^2+2ab+b^2

x^2+2x+1=(x+1)^2

(x+1)^2−y^2

a^2−b^2=(a−b)(a+b)

(x+1)^2−y^2=(x+1−y)(x+1+y)

=(x−y+1)(x+y+1)

Answer 2

\(x^2\) + 2\(x\) + 1 - y\(^2\)

= (\(x^2\) + 2.\(x\).1 + 1\(^2\)) - y\(^2\)

= (\(x+1\))\(^2\) - y\(^2\)

= (\(x+1-y\))(\(x+1+y\))

Answer 3

\(x^2+2x+1-y^2\)

\(=\left(x+1\right)^2-y^2\)

=(x+1+y)(x+1-y)