\(\left(x-\dfrac{1}{2}\right)^3=3^3\)
\(\Rightarrow x - \dfrac{1}{2} = 3\)
\(\Rightarrow x = 3 + \dfrac{1}{2}\)
\(\Rightarrow x = \dfrac{6}{2} + \dfrac{1}{2}\)
\(\Rightarrow x = \dfrac{7}{2}\)
\(\dfrac{1}{2}\) . \(x\) + \(\dfrac{3}{5}\) . (\(x\) - 2) =3
3 - (\(\dfrac{1}{6}\) - \(x\)) . \(\dfrac{2}{3}\) = \(\dfrac{2}{3}\)
\(\dfrac{x}{5}=\dfrac{4}{-3}\) và x\(^2\)+y\(^2\)=34
\(\dfrac{x}{4}=\dfrac{y}{7}\) và x\(^2\)-\(\)y\(^2\)= -33
2\(\dfrac{3}{x}\)=\(\dfrac{13}{x}\)
(với x≠0)
tớ cảm ơn nhiều<33
2\(\dfrac{3}{x}\)=\(\dfrac{13}{x}\)
(với x≠0)
tớ cảm ơn nhiều<33
\(\dfrac{2}{x}\)+\(\dfrac{1}{y}\)=\(\dfrac{1}{6}\) (x,y thuộc N)
Giúp mình vs ạ!!
Mình camon nhìuuu<33
a) \(\dfrac{2}{3}\)+\(\dfrac{3}{4}\).\(\left(-\dfrac{4}{9}\right)\)
b) \(-\dfrac{5}{7}\).\(\dfrac{31}{33}\)+\(-\dfrac{5}{7}\):\(\dfrac{33}{2}\)
c) \(-\dfrac{3}{5}\).\(\dfrac{13}{11}\) _ \(-\dfrac{3}{5}\).\(\dfrac{2}{11}\)
\(\dfrac{x}{y}\) = \(\dfrac{3}{4}\) và -3x + 5y = 33
Các bạn cho mình xin 2 cách làm với
giúp em với ạ. em cần gấp. camon
Tính bằng cách hợp lí:
a, 2 - (\(\dfrac{3}{7}\)+\(\dfrac{1}{3}\)) - (2- \(\dfrac{4}{3}\)+\(\dfrac{2}{7}\)) + 2 - (4-\(\dfrac{5}{7}\))
b, \(\dfrac{-3}{13}\) . (\(\dfrac{44}{33}\)+\(\dfrac{4444}{3030}\)+\(\dfrac{444444}{404040}\))
\(\dfrac{3}{8}.19\dfrac{1}{3}-\dfrac{3}{8}.33\dfrac{1}{3}\)
