Question

\(\dfrac{1}{2}\) . \(x\) + \(\dfrac{3}{5}\) . (\(x\) - 2) =3

3 - (\(\dfrac{1}{6}\) - \(x\)) . \(\dfrac{2}{3}\) = \(\dfrac{2}{3}\)

Answer 1

`@` `\text {Ans}`

`\downarrow`

`1/2*x + 3/5*(x - 2) = 3`

`=> 1/2*x + 3/5*x - 3/5*2 = 3`

`=> 1/2x + 3/5x - 6/5 = 3`

`=> (1/2 + 3/5)x - 6/5 = 3`

`=> 11/10x - 6/5 = 3`

`=> 11/10x = 3 + 6/5`

`=> 11/10x =21/5`

`=> x = 21/5 \div 11/10`

`=> x = 42/11`

Vậy, `x = 42/11`

____

`3 - (1/6 - x)*2/3 = 2/3`

`=> (1/6 - x)*2/3 = 3 - 2/3`

`=> (1/6 - x)*2/3 = 7/3`

`=> 1/6 - x = 7/3 \div 2/3`

`=> 1/6 - x=7/2`

`=> x = 1/6 - 7/2`

`=> x = -10/3`

Vậy, `x = -10/3.`

Answer 2

\(\dfrac{1}{2}\cdot x+\dfrac{3}{5}\left(x-2\right)=3\\ \dfrac{1}{2}\cdot x+\dfrac{3}{5}\cdot x-\dfrac{13}{5}=3\\ \left(\dfrac{1}{2}+\dfrac{3}{5}\right)x-\dfrac{13}{5}=3\\ \dfrac{11}{10}x-\dfrac{13}{5}=3\\ \dfrac{11}{10}x=\dfrac{28}{5}\\ x=\dfrac{28}{5}:\dfrac{11}{10}\\ x=\dfrac{28}{11}\\ 3-\left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{2}{3}\\ \left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=3-\dfrac{2}{3}\\ \left(\dfrac{1}{6}-x\right)\cdot\dfrac{2}{3}=\dfrac{7}{3}\\ \dfrac{1}{6}-x=\dfrac{7}{3}:\dfrac{2}{3}\\ \dfrac{1}{6}-x=\dfrac{7}{2}\\ x=\dfrac{1}{6}-\dfrac{7}{2}\\ x=-\dfrac{10}{3}\)

Answer 3

 

x= 4211