\(\left(x-3\right)\left(2x+6\right)+6=6\)
\(\left(x-3\right)\left(2x+6\right)=0\)
\(\left(x-3\right)\left(x+3\right)=0\)
\(x^2-9=0\)
\(x^2=9\)
⇒ \(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
\(\Leftrightarrow2x^2+6x-6x-18+6=6\)
\(\Leftrightarrow\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)