Ta có: \(\left|x-\dfrac{2}{3}\right|=\left|x+4\right|\)
=>\(\left[{}\begin{matrix}x-\dfrac{2}{3}=x+4\\x-\dfrac{2}{3}=-x-4\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}-\dfrac{2}{3}=4\left(vôlý\right)\\2x=-4+\dfrac{2}{3}\end{matrix}\right.\)
=>\(2x=-4+\dfrac{2}{3}=-\dfrac{12}{3}+\dfrac{2}{3}=-\dfrac{10}{3}\)
=>\(x=-\dfrac{10}{3}:2=-\dfrac{5}{3}\)