\(\left(x-1\right)^4\cdot3^2=\left(-12\right)^2\)
\(\Leftrightarrow\left(x-1\right)^4=4^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
\(\left(x-1\right)^4\cdot3^2=\left(-12\right)^2\)
\(\Leftrightarrow\left(x-1\right)^4=4^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
1, 2. 3x+2+4.3x+1=10 . 36
2, 4.3x-2+2.3x+1=4.36+2 .30
Tìm x biết :
\(a,2^x=\frac{8^4}{16^3}\)
\(b,\left(-2\right)^x=-4^6-8^5\)
\(c,4^x=4.4^{10}-3.4^{10}\)
\(d,4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(e,\left(\frac{1}{3}+\frac{1}{6}\right).2^x+2^{x+1}=2^{12}+2^{10}\)
Ai nhanh mk sẽ tik nha , cám ơn m.n nhiều lắm
\(4.3^{x-1}+2.3^{x+2}=4.3^4+2.3^9\)
tim x,y,z nguyen duong sao cho
1+4.3^x+4.3^y=z^2
Tim x :
\(a.\left\{\frac{1}{2}-\frac{1}{3}\right\}.6^x+6^{x+2}=6^{10}+6^7\)
\(b.\left\{\frac{1}{2}-\frac{1}{6}\right\}.3^{x+4}-4.3^x=3^{16}-4.3^{13}\)
ai nhanh mk tk !
bài 1 tính B = \(\frac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}\)
Tìm x: \(3^{x+2}+4.3^{x+1}+3^{x-1}=6^6\)
HELP ME!
tìm x
3^(x+2)+4.3^(x+1)=7.3^6
\(\frac{25.\left(-2\right)^{11}-2^{12}.10}{2^4.3^2.40}\)