(x - 1)3 = 8
=> (x - 1)3 = 23
=> x - 1 = 2
=> x = 3
(x - 1)3 = 8
=> (x - 1)3 = 23
=> x - 1 = 2
=> x = 2 + 1 = 3
ta có (x-1)3 =8
=>(x-1)3=23
=>x-1=2
=>x=2+1
vậy x=3
(x - 1)3 = 8
=> (x - 1)3 = 23
=> x - 1 = 2
=> x = 3
(x - 1)3 = 8
=> (x - 1)3 = 23
=> x - 1 = 2
=> x = 2 + 1 = 3
ta có (x-1)3 =8
=>(x-1)3=23
=>x-1=2
=>x=2+1
vậy x=3
\(b) 5^{x+4} - 3 . 5^{x+3} = 2. 5^{11} \)
\(c) 2 . 3^{x+2} + 4 . 3^{x+1} = 10 . 3 ^{6}\)
\(d) 6 . 8 ^ {x-1} + 8 ^ {x+1} = 6 . 8^ {19} + 8 ^ {21}\)
Tìm x biết:
a) 6* 8^x-1 + 8^x+1 = 6* 8^19 + 8^21
b) 4* 3^x-1 + 2* 3^x+2 = 4* 3^6 +2* 3^9
tìm x biết
1) x=-1/2 + 3/4 2) x - 1/5 = 2/11 3) x - 5/6 = 16/42 + -8/56
4) x/5 = 5/6 + -19/30 5) |x| - 1/4 = 6/18 6)x = -1/2 +3/4
7) x/15 = 3/5 + -2/3 8)11/8 + 13/6 = 85/x 9) x - 7/8 = 13/12
10) x - -6/15 = 4/27 11) -\(\dfrac{-6}{12}\)+ x = 9/48 12) x - 4/6 = 5/25 + -7/15
2/(x-1)(x-3)+5/(x-3)(x-8)+12/(x-8)(x-20)-1/x-20=-3/4
b,2 / (x-1). (x-3)+5 / (x-3).(x-8)+12 / (x-8).(x-20)-1 / x-20=-3/4
Tìm x
1/ (x - 1/2)^3 = 8
2/ (x - 1)^3 = 8/27
3/ (x - 2/3)^x = 1/81
a,5^x+4-3×5^x+3=2×5^11
b,3×5^x+2+4×5^x-3=19×5^10
c,6×8^x-1+8^x-1=6×8^19+8^21
d,5×2^x+3×2^x+2=5×2^5+3×2^7
Tìm x, biết:
2/(x-1)(x-3)+5/(x-3)(x-8)+12/(x-8)(x-20)-1/x-20=-3/4
8/5 x 2/3 + 8/5 x 1/3 - 8/5