Question

( x + 1/2 ). ( 2/3 -2x )= 0

Answer 1

TH1:x+1/2=0

x=-1/2

TH2:2/3-2x=0

2x=2/3-0

2x=2/3

x=1/3

x thuộc (-1/2 , 1/3)

Answer 2

`( x + 1 / 2 ) . ( 2 / 3 - 2x ) = 0`

`@TH1: x + 1 / 2 = 0`

      `=> x = [-1] / 2`

`@TH2: 2 / 3 - 2x = 0`

       `=> 2x = 2 / 3`

      `=> x = 2 / 3 : 2`

      `=> x = 1 / 3`

Vậy `x = 1 / 3` hoặc `x =[-1] / 2`

Answer 3

`(x + 1/2) . (2/3 - 2x) = 0`

$\\$

`<=>` `{(x + 1/2 = 0),(2/3 - 2x = 0):}`

$\\$

`<=>` `{(x = -1/2),(x = 1/3):}`

Vậy `x = {-1/2; 1/3}`

Answer 4

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\-2x=-\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)

Answer 5

\(\left(x+\dfrac{1}{2}\right)\cdot\left(\dfrac{2}{3}-2x\right)=0\)

Th1 : \(x+\dfrac{1}{2}=0\)

         \(x=0-\dfrac{1}{2}\)

        \(x=-\dfrac{1}{2}\)

Th2 : \(\dfrac{2}{3}-2x=0\)

                 \(2x=\dfrac{2}{3}-0\)

                 \(2x=\dfrac{2}{3}\)

                   \(x=\dfrac{2}{3}:2\)

                  \(x=\dfrac{1}{3}\)

Vậy \(x=\left[{}\begin{matrix}-\dfrac{1}{2}\\\dfrac{1}{3}\end{matrix}\right.\)