Question

(x - 1 ) . ( x +2) . (-x - 3) = 0

Tìm các số nguyên x , thỏa mãn :

( x - 7 ) ( x + 3 ) < 0

Answer 1

a: (x-1)(x+2)(-x-3)=0

=>(x-1)(x+2)(x+3)=0

=>\(\left[{}\begin{matrix}x-1=0\\x+2=0\\x+3=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)

b: (x-7)(x+3)<0

TH1: \(\left\{{}\begin{matrix}x-7>0\\x+3< 0\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x>7\\x< -3\end{matrix}\right.\)

=>\(x\in\varnothing\)

TH2: \(\left\{{}\begin{matrix}x-7< 0\\x+3>0\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x< 7\\x>-3\end{matrix}\right.\)

=>-3<x<7

mà x nguyên

nên \(x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\)