Question

(x + 1) . (6 - 3x) = 0 Giải chi tiết được ko ạ ?

Answer 1

\(x\in\left\{-1;2\right\}\)

Answer 2

\(\left[{}\begin{matrix}x+1=0\\6-3x=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\left(-1\right)\\x=2\end{matrix}\right.\)

Answer 3

(x+1)(6-3x)=0

6x-3x\(^2\)+6-3x=0

-3x\(^2\)+3x+6=0                                                                                                  [x+1=0

[6−3x=0

[x+1=0

[6−3x=0
[x=(−1)

[x=2