a, \(27-x^3=\left(3-x\right)\left(9+3x+x^2\right)\)
b, \(\dfrac{x^3}{64}-\dfrac{y^3}{125}=\left(\dfrac{x}{4}\right)^3-\left(\dfrac{y}{5}\right)^3\)
\(=\left(\dfrac{x}{4}-\dfrac{y}{5}\right)\left(\dfrac{x^2}{16}+\dfrac{xy}{20}+\dfrac{y^2}{25}\right)\)
Chúc bạn học tốt!!!