\(\left(\sqrt{3}\right)^2=3< 49=7^2\\ \Rightarrow2+\sqrt{3}< 2+7=9\\ \Rightarrow\sqrt{2+\sqrt{3}}< \sqrt{9}=3\\ \Rightarrow1+\sqrt{2+\sqrt{3}}< 1+3=4\\ \Rightarrow\sqrt{1+\sqrt{2+\sqrt{3}}}< \sqrt{4}=2\)
\(A=\dfrac{\sqrt{2+\sqrt{4+2\sqrt{3}}}}{\sqrt{2}}=\dfrac{\sqrt{3+\sqrt{3}}}{\sqrt{2}}< 2\)
(√3)2=3<49=72⇒2+√3<2+7=9⇒√2+√3<√9=3⇒1+√2+√3<1+3=4⇒√1+√2+√3<√4=2
cho mik gui nha