Ta có: m dd H2SO4 = 200.1,14 = 228 (g)
\(\Rightarrow m_{H_2SO_4}=228.9,8\%=22,344\left(g\right)\)
\(\Rightarrow n_{H_2SO_4}=\dfrac{22,344}{98}=0,228\left(mol\right)\)
PT: \(2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O\)
a, Theo PT: \(n_{NaOH}=2n_{H_2SO_4}=0,456\left(mol\right)\)
\(\Rightarrow m_{ddNaOH}=\dfrac{0,456.40}{4\%}=456\left(g\right)\)
b, Theo PT: \(n_{Na_2SO_4}=n_{H_2SO_4}=0,228\left(mol\right)\)
\(\Rightarrow C\%_{Na_2SO_4}=\dfrac{0,228.142}{456+228}.100\%\approx4,73\%\)
Đúng 2
Bình luận (0)
