\(A=\dfrac{sin30^0+2\cdot cos45^0-3\cdot tan^{2024}45^0}{cos60^0}\)
\(=\dfrac{\dfrac{1}{2}+2\cdot\dfrac{\sqrt{2}}{2}-3}{\dfrac{1}{2}}=\dfrac{-\dfrac{5}{2}+\dfrac{2\sqrt{2}}{2}}{\dfrac{1}{2}}=\dfrac{2\sqrt{2}-5}{2}\cdot2=2\sqrt{2}-5\)
\(B=\dfrac{sin30^0\cdot cos60^0\cdot cot60^0}{tan45^0}\)
\(=\dfrac{\dfrac{1}{2}\cdot\dfrac{1}{2}\cdot\dfrac{\sqrt{3}}{3}}{1}=\dfrac{\sqrt{3}}{12}\)