a, \(\dfrac{3}{1}:\dfrac{5}{7}=\dfrac{3}{1}\times\dfrac{7}{5}=\dfrac{21}{5}\)
b, \(\dfrac{2}{3}+\dfrac{1}{2}=\dfrac{4}{6}+\dfrac{3}{6}=\dfrac{7}{6}\)
a \(3\times\dfrac{7}{5}=\dfrac{21}{5}\)
b \(\dfrac{2}{3}+\dfrac{1}{2}=\dfrac{4}{6}+\dfrac{3}{6}=\dfrac{7}{6}\)