\(\dfrac{2}{3}\) - 4 x (\(\dfrac{1}{2}\)+\(\dfrac{3}{4}\))
=\(\dfrac{2}{3}\)-4 x\(\dfrac{5}{4}\)=\(\dfrac{2}{3}\)-5=\(\dfrac{-13}{3}\)
KL:...
Ta có: \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\)
\(=\dfrac{2}{3}-4\cdot\dfrac{5}{4}\)
\(=\dfrac{2}{3}-\dfrac{15}{3}=\dfrac{-13}{3}\)