a.\(V_{NaCl}=\dfrac{n}{C_M}=\dfrac{0,5}{2}=0,25l\)
b.\(n_{HCl}=\dfrac{9.10^{22}}{6.10^{23}}=0,15mol\)
\(V_{HCl}=\dfrac{n}{C_M}=\dfrac{0,15}{0,5}=0,3l\)
c.\(n_{NH_3}=\dfrac{4,48}{22,4}=0,2mol\)
\(V_{NH_3}=\dfrac{n}{C_M}=\dfrac{0,2}{1,5}=0,13l\)
d.\(V_{NaOH}=\dfrac{n}{C_M}=\dfrac{2,5}{1,25}=2l\)