=4/25+3/100+41/100+37/100
=16/100+81/100=97/100
\(\dfrac{4}{25}+6\%+\dfrac{41}{100}+0,37=\dfrac{4}{25}+\dfrac{3}{50}+\dfrac{41}{100}+\dfrac{37}{100}=\dfrac{16}{100}+\dfrac{6}{100}+\dfrac{41}{100}+\dfrac{37}{100}=\left(\dfrac{16}{100}+\dfrac{37}{100}\right)+\left(\dfrac{6}{100}+\dfrac{41}{100}\right)=\dfrac{53}{100}+\dfrac{47}{100}=\dfrac{100}{100}=1\)