\(n_{Al_2O_3}=\dfrac{10,2}{102}=0,1\left(mol\right)\\ PTHH:Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\\ n_{H_2SO_4}=3.0,1=0,3\left(mol\right)\\ m_{H_2SO_4}=\dfrac{29,4.100}{29,4}=100\left(g\right)\\ V_{ddH_2SO_4}=\dfrac{100}{1,14}\approx87,719\left(ml\right)\)
\(n_{Al_2O_3}=\dfrac{10,2}{102}=0,1\left(mol\right)\)
PTHH: \(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
0,1------->0,3
\(\Rightarrow m_{H_2SO_4}=0,3.98=29,4\left(g\right)\)
\(\Rightarrow m_{dd.H_2SO_4}=\dfrac{29,4.100}{29,4}=100\left(g\right)\)
=> \(V_{dd.H_2SO_4}=\dfrac{100}{1,14}=\dfrac{5000}{57}\left(ml\right)\)
