\(\left(\sqrt{6}-\sqrt{2}\right)\left(\sqrt{2+\sqrt{3}}\right)\)
\(=\sqrt{2}\left(\sqrt{3}-1\right)\left(\sqrt{2+\sqrt{3}}\right)\)
=\(\left(\sqrt{3}-1\right)\sqrt{4+2\sqrt{3}}\) (nhân \(\sqrt{2}\) vào \(\sqrt{2+\sqrt{3}}\))
=\(\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)\)
=3-1=2