S=1/22+1/23+1/24+...+1/2100
=>2S=1/2+1/22+1/23+...+1/299
=>2S-S=(1/2+1/22+1/23+...+1/299)-(1/2+1/22+1/23+...+1/299)
=> S=1/2-1/2100
\(2S=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}\)
\(2S-S=S=\frac{1}{2}-\frac{1}{2^{100}}\)
S=1/22+1/23+1/24+...+1/2100
=>2S=1/2+1/22+1/23+...+1/299
=>2S-S=(1/2+1/22+1/23+...+1/299)-(1/2+1/22+1/23+...+1/299)
=> S=1/2-1/2100
\(2S=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}\)
\(2S-S=S=\frac{1}{2}-\frac{1}{2^{100}}\)
Tính hợp lí
a) A = 1 + 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100 .
b) B = 5 + 5 3 + 5 5 + . . . + 5 97 + 5 99 .
Tính hợp lí:
a, A = 1 + 2 + 2 2 + 2 3 + 2 4 + . . . + 2 99 + 2 100
b, B = 5 + 5 3 + 5 5 + . . . + 5 97 + 5 99
a)[600-(40:23+3.53)]:5 b)16.122-(4.232-59.4)
c)2100-(1+2+22+23+...+299) d)169.20110-17.(83-1702:23+12012)+27:24
Đề bài:Thực hiện phép tính
1+2+22+23+24+....2100 = ?
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A=2100-299+298-297+...-23+22-2+1
HELP ME
a, A = 1 + 2 + 22 + 23 + ... + 250 =
b, B = 1 + 3 + 32 + 33 + ... 3100 =
c, C = 5 + 52 + 53 + ... 530 =
d, D = 2100 = 299 + 298 - 297 + ... + 22 - 2
Cho biểu thức A = 1 + 21 + 22 + 23 +...+ 2100 + 2101 .Chứng minh A chia hết cho 7
Bài 5: (1 điểm) Cho A= 2+22+23+24+.....+2100 . Chứng minh A chia hết cho 3.
Tính S= 1/22+1/23+...+1/22005
cho S=1+2+22+23+24+25+26+27
chứng tỏ rằng S chia hết cho 3