\(A=x^3+3xy^2-9+y\left(3x^2+y^2\right)\)
\(=x^3+3x^2y+3xy^2+y^3-9\)
\(=\left(x+y\right)^3-9\)
\(=\left(1,95+0,05\right)^3-9=2^3-9=-1\)
\(B=x^2+\frac{1}{2}x+\frac{1}{16}\)
\(=x^2+2.x.\frac{1}{4}+\left(\frac{1}{4}\right)^2\)
\(=\left(x+\frac{1}{4}\right)^2\)
\(=\left(9,75+0,25\right)^2=10^2=100\)