Question

Tính khối lượng phân tử theo đơn vị amu của các chất sau Al²O³,CU(OH)²

Answer 1

`@` `\text {dnammv}`

\(\text{Al}_2\text{O}_3:\)

`- \text {NTK:}`

\(+\text{Al: 27 amu}\)

\(+\text{O: 16 amu}\)

`->`\(\text{PTK}_{\text{Al}_2\text{O}_3}=27\cdot2+16\cdot3=102\text{ }< \text{amu}>\)

 

\(\text{Cu(OH)}_2:\)

`- \text {NTK:}`

\(+\text{Cu: 64 amu}\)

\(+\text{H: 1 amu}\)

\(+\text{O: 16 amu}\)

`->`\(\text{PTK}_{\text{Cu}\left(\text{OH}\right)_2}=64+\left(16+1\right)\cdot2=98\text{ }< \text{amu}>.\)