\(m_{CuSO_4\left(8\%\right)}=500\cdot8\%=40\left(g\right)\)
\(n_{CuSO_4\cdot5H_2O}=a\left(mol\right)\)
\(\Rightarrow n_{CuSO_4}=a\left(mol\right)\)
\(m_{CuSO_4\left(15\%\right)}=160a+40\left(g\right)\)
\(m_{dd_{CuSO_4\left(15\%\right)}}=250a+500\left(g\right)\)
\(C\%_{CuSO_4}=\dfrac{160a+40}{250a+500}\cdot100\%=15\%\)
\(\Leftrightarrow a=\dfrac{2}{7}\)
\(m_{CuSO_4\cdot5H_2O}=\dfrac{2}{7}\cdot250=71.42\left(g\right)\)