Question

Tính hợp lí

 4\(\dfrac{1}{6}\)- 2\(\dfrac{1}{3}\)+ 3\(\dfrac{7}{12}\) - 5\(\dfrac{3}{4}\)

Answer 1

\(=4+\dfrac{1}{6}-2-\dfrac{1}{3}+3+\dfrac{7}{12}-5-\dfrac{3}{4}\)

\(=\dfrac{1}{6}-\dfrac{1}{3}+\dfrac{7}{12}-\dfrac{3}{4}=\dfrac{2}{12}-\dfrac{4}{12}+\dfrac{7}{12}-\dfrac{9}{12}=0\)

Answer 2

\(=4+\dfrac{1}{6}-2-\dfrac{1}{3}+3+\dfrac{7}{12}-5-\dfrac{3}{4}\)

\(=\left(4-2+3-5\right)+\left(\dfrac{1}{6}-\dfrac{1}{3}+\dfrac{7}{12}-\dfrac{3}{4}\right)\)

\(=0+\dfrac{2-4+7-9}{12}\)

\(=\dfrac{-4}{12}=\dfrac{-1}{3}\)