Question

tính giá trị biểu thức :

\(\frac{4^6.3^4.9^5}{6^{12}}\)

 

Answer 1

\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{2^{12}.3^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)

Answer 2

\(\frac{4^6\cdot3^4\cdot9^5}{6^{12}}\)

\(=\frac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}\)

\(=\frac{1\cdot3^{14}}{1\cdot3^{12}}\)

\(=\frac{3^{14}}{3^{12}}\)

\(=3^2\)

\(=9\)