\(\dfrac{7}{3}-\dfrac{13}{9}+3+\dfrac{4}{9}\\ =\left(\dfrac{7}{3}+3\right)+\left(\dfrac{4}{9}-\dfrac{13}{9}\right)\\ =\dfrac{16}{3}+\left(\dfrac{-9}{9}\right)\\ =\dfrac{16}{3}-1\\ =\dfrac{13}{3}\)
\(=\dfrac{7}{3}-\left(\dfrac{13}{9}-\dfrac{4}{9}\right)+3=\dfrac{7}{3}-1+3=\dfrac{7}{3}+2=\dfrac{13}{3}\)