Question

Tính bằng cách thuận tiện:

\(\frac{8}{9}\)+\(\frac{14}{27}\)+\(\frac{1}{9}\)                    \(\frac{1}{2}\)+\(\frac{3}{4}\)+\(\frac{1}{2}\)

Answer 1

Ta có \(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}=1+\frac{14}{27}=\frac{41}{27}\)

Ta có \(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)

Answer 2

\(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}=1+\frac{14}{27}=\frac{41}{27}\)

\(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)

Answer 3

8/9+14/27+1/9

=(8/9+1/9)+14/27

=1+14/27

=27/27+14/27

=31/27

1/2+3/4+1/2

=(1/2+1/2)+3/4

=1+3/4

=7/4

Answer 4

\(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}\)

\(=1+\frac{14}{27}=\frac{27}{27}+\frac{14}{27}=\frac{41}{27}\)

\(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{4}{4}+\frac{3}{4}=\frac{7}{4}\)

Answer 5

\(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}=1+\frac{14}{27}=\frac{27}{27}+\frac{14}{27}=\frac{31}{27}\)\(\frac{41}{27}\)           

\(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)    

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