\(\dfrac{4}{7}x\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{4}{7}x1=\dfrac{4}{7}\)
2/5 x 4/7 + 3/5 x 4/7
= (2/5 + 3/5 ) x 4/7
= 1 x 4/7
= 4/7
2/5 *4/7+3/5*4/7
=( 2/5 + 3/5 ) *4/7
= 1 * 4/7
= 4/7
4/7x(2/5+3/5)=4/7x1=4/7x(2/5+3/5)=4/7x1=4/7
\(\dfrac{4}{7}\cdot\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)=\(\dfrac{4}{7}\cdot1\)=\(\dfrac{4}{7}\)