Question

Tính bằng cách thuận tiện

5/6x3+20/6x2-1:6/5

Answer 1

\(\dfrac{5}{6}\times3+\dfrac{20}{6}\times2-1:\dfrac{6}{5}\)
\(=\dfrac{5}{6}\times3-\dfrac{5}{6}+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times\left(3-1\right)+\dfrac{20}{6}\times2\)
\(=\dfrac{5}{6}\times2+\dfrac{20}{6}\times2\)
\(=\left(\dfrac{5}{6}+\dfrac{20}{6}\right)\times2\)
\(=\dfrac{25}{6}\times2\)
\(=\dfrac{25}{3}\)

#DatNe

Answer 2

\(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - 1 : \(\dfrac{6}{5}\)

= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{20}{6}\) \(\times\) 2 - \(\dfrac{5}{6}\)

= \(\dfrac{5}{6}\) \(\times\) 3 + \(\dfrac{5}{6}\) \(\times\) 8 - \(\dfrac{5}{6}\) \(\times\)1

= \(\dfrac{5}{6}\) \(\times\) ( 3 + 8 - 1)

= \(\dfrac{5}{6}\) \(\times\)10

= \(\dfrac{25}{3}\)

Answer 3

\(\dfrac{5}{6}\times3+\dfrac{20}{6}\times2-1:\dfrac{6}{5}\)

\(=\dfrac{5}{6}\times3+\dfrac{10}{3}\times2-1\times\dfrac{5}{6}\)

\(=\dfrac{5}{6}\times\left(3+8-1\right)\)

\(=\dfrac{5}{6}\times10\)

\(=\dfrac{25}{3}\)