\(2\dfrac{1}{3}+1\dfrac{1}{2}=\dfrac{7}{3}+\dfrac{3}{2}=\dfrac{21}{6}+\dfrac{9}{6}=\dfrac{30}{6}=5\)
\(1\dfrac{1}{4}-\dfrac{6}{5}=\dfrac{5}{4}-\dfrac{6}{5}=\dfrac{25}{20}-\dfrac{24}{20}=\dfrac{1}{20}\)
\(426\times325=138450\)
\(1104
:
23=48\)
a)
\(2\dfrac{1}{3}+1\dfrac{1}{2}=\dfrac{7}{3}+\dfrac{3}{2}=\dfrac{23}{6}\)
b)
\(1\dfrac{1}{4}-\dfrac{6}{5}=\dfrac{5}{4}-\dfrac{6}{5}=\dfrac{1}{20}\)
c)
\(426\cdot325=138450\)
d)
\(1104:23=48\)