\(a,xy+y+x=4\)
\(y\left(x+1\right)+x+1=5\)
\(\left(y+1\right)\left(x+1\right)=5\)
Lập bảng là ra
\(b,xy-2y-x-4=0\)
\(y\left(x-2\right)-x+2=6\)
\(\left(y-1\right)\left(x-2\right)=6\)
Lập bảng là ra
x.y+y+x=4
=>x.(y+1)+y=4
=>x.(y+1)+y+1=5
=>(y+1)(x+1)=5
=>x+1 E { 1;5 }
y+1 E { 1;5 }
=> x E { 0;4}
y E { 0;4}
x;y E { 0;4};{4;0}
b, y.(x-2)=x+4
=>y.x-2.y=x+4
=>2.y.x-2.y=x+4+x.y
=>2y(x+1)=x.(y+1)
=>x.2y+2y=x.y+x
=>x.2y+2y-x.y-x=0
=>x.y+2y-x=0
x(y-1)+2y=0