Ta có: \(x^3-4x^3=-4x\)
=>\(-3x^3=-4x\)
=>\(3x^3=4x\)
=>\(3x^3-4x=0\)
=>\(x\left(3x^2-4\right)=0\)
=>\(\left[{}\begin{matrix}x=0\\3x^2-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x^2=\dfrac{4}{3}\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=0\\x=\dfrac{2\sqrt{3}}{3}\\x=-\dfrac{2\sqrt{3}}{3}\end{matrix}\right.\)
a.4x^3-4x^2+x=0
b.x.(x-3)+12-4x=0
c.x^3+3x^2+3x-7=0
*tìm x*
Tìm Min :
a, Y = (x+2)(x+3)(x+4)(x+5) - 24
b, Y= (4x+1)(4x+2)(4x+3)(4x+4)-3
tìm x , biết
a. 4x(x-5)-(x-1)(4x-3)=5
b. (3x-4)(x-2) = 3x(x-9)-3
c.2(x+3)-x2 -3x=0
d. 8x3-50x=0
e. (4x-30)2-3x(3-4x)
Tìm x X^3+4x^2+4x+3=0
Cho biểu thức A=(3+x/3-x - 3 -x/3+x - 4x^2/x^2-9) : (5/3-x - 4x+2/3x-x^2) a. Rút gọn A b. Tìm x để A=3 c.tìm x để A>4x
tìm x biết:
a)2(x+3)+x(3+x)=0
b)(2x-3)^2-(4x-6)(x+2)+x^2+4x+4=0
4x(x-5)-(x-1)(4x-3)=5 tìm x
Tìm x biết : (4x+3)(4x-3)-(4x-5)^2=46
tìm x : x^3-4x^2+4x=o
tìm x biết
a)4x^2+4x-3=0
b)x^4-3x^3-x+3=0
c)x^2(x-1)-4x^2+8x-4=0
