\(\dfrac{x}{12}=x+\dfrac{15}{16}\)
\(\Leftrightarrow\dfrac{x}{12}=\dfrac{16x+15}{16}\)
\(\Rightarrow12\left(16x+15\right)=16x\)
\(\Leftrightarrow192x+180=16x\)
\(\Leftrightarrow176x=-180\)
\(\Leftrightarrow x=-\dfrac{45}{44}\)
Vậy \(x=-\dfrac{45}{44}\)
\(\dfrac{x}{12}=\dfrac{x+15}{16}\)
\(\Rightarrow12\left(x+15\right)=16x\)
\(\Leftrightarrow12x+180=16x\)
\(\Leftrightarrow4x=180\)
\(\Leftrightarrow x=45\)
Vậy x = 45
\(\dfrac{x}{12}=\dfrac{x+15}{16}\)
\(16x=12\left(x+15\right)\)
\(16x=12x+180\)
\(4x=180\)
\(x=45\)