Question

Tìm x:

x + 50/ x + 68 = x -15/ x - 10

Answer 1

`(x+50)/(x+68)=(x-15)/(x-10)`

`=>(x+50)(x-10)=(x+68)(x-15)`

`=> x^2 - 10x + 50x - 500 = x^2 - 15x + 68x - 1020`

`=> x^2 + 40x - 500 = x^2 + 53x - 1020`

`=> 40x - 53x = -1020 + 500`

`=> -13x=-520`

`=> x =-520:(-13)`

`=>x=40`

Vậy: `x=40`

Answer 2

`(x + 50)/(x + 68)=(x-15)/(x-10)`

Điều kiện: `x ne - 68; x ne 10`

Phương trình `=> (x + 50)(x-10) = (x + 68)(x-15)`

`=> x^2 - 10x + 50x - 500 = x^2 - 15x + 68x - 1020`

`=> x^2 +40x - 500 = x^2  +53x - 1020`

`=> 40x - 500 = 53x - 1020`

`=> 53x - 40x = 1020 - 500`

`=> 13x = 520`

`=> x = 520 : 13`

`=> x= 40` (Thỏa mãn)

Vậy `x = 40`