\(\Leftrightarrow4x^2+x-8x-2-4x^2-27x=1\)
=>-34x=3
hay x=-3/34
\(\left(x-2\right)\left(4x+1\right)-4x\left(x+7\right)=1\\ \Rightarrow4x^2-8x+x-2-4x^2-28x=1\\ \Rightarrow-35x=3\\ \Rightarrow x=\dfrac{-3}{35}\)
(x - 2)(4x + 1) - 4x(x+7) = 1
⇔ 4x2 + x - 8x - 2 - 4x2 - 28x = 1
⇔ - 35x = 3
⇔ x = - 3/35