a: =(x+3)^3=64/27
=>x+3=4/3
=>x=-5/3
b: =>x=0 hoặc x-1/7=0
=>x=0 hoặc x=1/7
c: =>x-1/5=0
=>x=1/5
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\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
Bài 2: Tìm x,y,z biết:
a)\(\left(x-1\right)\)\(:\)\(\dfrac{2}{3}\)=\(\dfrac{-2}{5}\)
b) \(\left|x-\dfrac{1}{2}\right|-\dfrac{1}{3}=0\)
c) \(\left|4x+2\right|=\left|6+2x\right|\)
Tìm x:a) dfrac{2}{3}+left(x-dfrac{1}{2}right)^3dfrac{19}{27}b) left(dfrac{3}{2}right)^{2x-1}:left(dfrac{27}{8}right)^3dfrac{81}{16}c) dfrac{1}{2}.2^x+4.2^x9.2^5d) text{12 - (2x +1)}^2-69
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Tìm x:
\(a\)) \(\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)
\(b\)) \(\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{27}{8}\right)^3=\dfrac{81}{16}\)
\(c\)) \(\dfrac{1}{2}.2^x+4.2^x=9.2^5\)
\(d\)) \(\text{12 - (2x +1)}^2=-69\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
\(\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\left(\dfrac{2}{3}x-1\right)\left(\dfrac{3}{4}x+\dfrac{1}{2}\right)=0\)
\(\dfrac{4}{9}:x=3\dfrac{1}{3}:2,25\)
\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)
Bài 1:
a) |2x - 3| - \(\dfrac{1}{3}\)= 0
b) \(\dfrac{5}{6}-\left|x+\dfrac{1}{4}\right|=\dfrac{1}{4}\)
c) \(\left|2x-1\right|-\left|x+\dfrac{1}{3}\right|=0\)
d) \(3x-\left|x+15\right|=\dfrac{5}{4}\)
Bài 2:
a) A= 1,3 + 2,5
b) B= -4,3 - 13,7 + (-5,7) - 6,3
c) C= 25.(-5).(-0,4).(-0,2)
d) D=|11,4 - 3.4| + |12,4 - 15,5|
4 tháng 5 2022 lúc 20:30
Câu 1: Thực hiện phép tính
a, \(40\dfrac{1}{4}:\dfrac{5}{7}-25\dfrac{1}{4}:\dfrac{5}{7}-\dfrac{1}{2021}\)
b, \(\left|\dfrac{-5}{9}\right|.\sqrt{81}-2021^0.\dfrac{16}{25}\)
Câu 2: Tìm x
\(3\left(x-\dfrac{1}{3}\right)-7\left(x+\dfrac{3}{7}\right)=-2x+\dfrac{1}{3}\)
a\(\dfrac{-3}{4}x+1=\dfrac{5}{6}\)
b \(\left(2x-3\right).\left(x-5\right)=0\)
c \(\dfrac{1}{2}-|x+1|=0,25\)
Tìm x, biết:
a) \(\dfrac{-3}{2}x+\dfrac{1}{4}=\dfrac{1}{2}\left(x+1\right)\)
b) \(\left(6-3\sqrt{x}\right)\left(\left|x\right|-7\right)=0\)