Các câu hỏi tương tự
1.
a) \(A=\frac{\left(\frac{2018}{1}-1\right)\left(\frac{2018}{2}-1\right)...\left(\frac{2018}{1000}-1\right)}{\left(\frac{1000}{1}+1\right)\left(\frac{1000}{2}+1\right)...\left(\frac{1000}{1007}+1\right)}\)
b) Tìm x biết 378% của x kém A 55 đơn vị.
2. Tìm a, b, c sao cho : \(\frac{\overline{ab}.\overline{bc}.\overline{ca}}{\overline{ab}+\overline{bc}+\overline{ca}}=\frac{3321}{11}\)
Tìm \(x\):
a, \(\overline{3x}+\overline{x3}=11\times11\);
b, \(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+...+\left(x+28\right)=195\);
c, \(\left(x-452\right):a=\overline{aaaa}\).
tìm x:
a,\(\frac{x}{2\times5}+\frac{x}{5\times8}+\frac{x}{8\times11}+\frac{x}{11\times14}=\frac{3}{7}\)
b, \(50\%+\frac{2}{3}x=x+4\)
c,\(0,5x-\frac{2}{3}\left(x+1\right)=\frac{-1}{12}\)
d,\(\frac{1}{2}\left(x-\frac{2}{3}\right)-\frac{2}{5}\left(2-x\right)=\frac{1}{9}\)
1.Tìm các chữ số a,b,c biết:\(\frac{1}{\overline{ab}.\overline{bc}}+\frac{1}{\overline{bc}.\overline{ca}}+\frac{1}{\overline{ca}.\overline{ab}}=\frac{11}{3321}\)
2.Tìm tất cả các số nguyên dương x;y thoả mãn:(x+y)4=40x+41
1(\(\left(\frac{4}{286}-\frac{2}{7\times9}\right)\left(\frac{4}{286}-\frac{2}{9\times11}\right)......\left(\frac{4}{286}-\frac{2}{97\times99}\right)\)
2)\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{19}+\frac{1}{20}}{\frac{19}{1}+\frac{18}{2}+\frac{17}{3}+...+\frac{2}{18}+\frac{1}{19}}\)
a) Tìm x :
1) \(\left(3x-1\right)\left(\frac{-1}{2}x+5\right)=0\)
2) \(4\frac{2}{3}:x=4\frac{4}{9}+1\)
3) \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
b) Tính :
\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
Tìm x
\(\frac{5}{2}-\left(\frac{3}{2}-2\frac{1}{3}+x\right)=\frac{8}{15}-\left(\frac{1}{4}-\frac{7}{10}\right)\)
\(1\frac{2}{3}-1\frac{3}{5}+x=\frac{2}{5}-\left|\frac{3}{4}-\frac{7}{8}\right|\)
\(2-\left(\frac{2}{3}-3\frac{1}{4}+x\right)=1\left|\frac{1}{6}-\frac{13}{12}\right|\)
Tìm x, biết
a, \(\left(\frac{12}{21}\right)^x=\left(\frac{3}{5}\right)^2-\left(-\frac{3}{5}\right)^4\)
b, \(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
Help me!!!
Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)