\(\Leftrightarrow x\in\left\{2;-2\right\}\)
\(\Rightarrow\left(x-2\right)\left(x+2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
(5x - 10) . (6x + 12) = 0
=>(5x - 10) = 0 hoặc (6x + 12) = 0
* TH1: (5x - 10) = 0 * TH2: (6x + 12) = 0
=>x = 2 => x = -2
Vậy x=2 hoặc x = -2