a)(2x+1)2=25=52=(-5)2
=>2x+1=5 hoặc 2x+1=-5
2x=5-1 2x=-5-1
2x=4 2x=-6
x=4/2 x=-6/2
x=2 x=-3
Vậy x=2 hoặc x=-3
b)(2x-3)2=36=62=(-6)2
=>2x-3=6 hoặc 2x-3=-6
2x=6+3 2x=-6+3
2x=9 2x=-3
x=9/2 x=-3/2
Vậy x=9/2 hoặc x=-3/2
(2x+1)2 = 25
=> 2x2 + 12 = 25
=> 2x2 + 1 = 25
=> 2x2 = 24
=> x2 = 12
=> x = \(\sqrt{12}\)
(2x - 3)2 = 36
=> 2x2 - (32) = 36
=> 2x2 - 9 = 36
=> 2x2 = 45
=> x2 = 22,5
=> x = \(\sqrt{22,5}\)
t i c k nha!! 65768769789890
a)(2x+1)2 =25
<=>(2x+1)2 =52
<=>2x+1=5
<=>2x=4
<=>x=2
b)(2x-3)2 =36
<=>(2x-3)2 =62
<=>2x-3=6
<=>2x=9
<=>x=4,5
\(\text{a)(2x+1)2 =25 }\)
<=>(2x+1)2 =52
<=>2x+1=5
<=>2x=4
<=>x=2
b)(2x-3)2 =36
<=>(2x-3)2 =62
<=>2x-3=6
<=>2x=9
<=>x=4,5
(2x+1)2=25
(2x+1)2=52
2x+1=5
2x=5-1=4
x=4 :2=2