a: \(\sqrt[3]{2x-1}-\sqrt[3]{x+7}=-1\)
=>\(\sqrt[3]{2x-1}+1-\sqrt[3]{x+7}=0\)
=>\(\sqrt[3]{2x-1}-1+2-\sqrt[3]{x+7}=0\)
=>\(\frac{2x-1-1}{\sqrt[3]{\left(2x-1\right)^2}+\sqrt[3]{2x-1}+1}+\frac{8-x-7}{2^2+2\cdot\sqrt[3]{x+7}+\sqrt[3]{\left(x+7\right)^2}}=0\)
=>\(\left(\frac{2}{\sqrt[3]{\left(2x-1\right)^2}+\sqrt[3]{2x-1}+1}+\frac{-1}{2^2+2\cdot\sqrt[3]{x+7}+\sqrt[3]{\left(x+7\right)^2}}\right)\cdot\left(x-1\right)=0\)
=>x-1=0
=>x=1
b: ĐKXĐ: x>=3/2
\(\sqrt[3]{x-1}+\sqrt{2x-3}=2\)
=>\(\sqrt[3]{x-1}-1+\sqrt{2x-3}-1=0\)
=>\(\frac{x-1-1}{\sqrt[3]{\left(x-1\right)^2}+\sqrt[3]{x-1}+1}+\frac{2x-3-1}{\sqrt{2x-3}+1}=0\)
=>\(\left(x-2\right)\left(\frac{1}{\sqrt[3]{\left(x-1\right)^2}+\sqrt[3]{x-1}+1}+\frac{2}{\sqrt{2x-3}+1}\right)=0\)
=>x-2=0
=>x=2(nhận)
