Question

TÌM X

(x+1)+(x+2)+(X+3)+...+(x+30)=500

 

Answer 1

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=500\)

Số lượng số hạng là: \(30-1+1=30\)

\(\Rightarrow30x+\dfrac{30\left(30+1\right)}{2}=500\)

\(30x+465=500\)

\(30x=35\)

\(x=\dfrac{7}{6}\)

Answer 2

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=500\)

\(\Rightarrow x+1+x+2+..+x+30=500\)

\(\Rightarrow\left(x+x+...+x\right)+\left(1+2+...+30\right)=500\)

\(\Rightarrow30\cdot x+465=500\)

\(\Rightarrow30\cdot x=500-465\)

\(\Rightarrow30\cdot x=35\)

\(\Rightarrow x=\dfrac{35}{30}\)

\(\Rightarrow x=\dfrac{7}{6}\)

Answer 3

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