Question

Tìm x : 

X x 2\(\dfrac{2}{3}\) = 3\(\dfrac{4}{8}\) + 6\(\dfrac{5}{12}\)

1 -  x = 2\(\dfrac{5}{12}\) : 3\(\dfrac{5}{9}\)

3\(\dfrac{7}{3}\)  x X - 2\(\dfrac{3}{4}\) = 3\(\dfrac{6}{12}\)  x \(\dfrac{10}{8}\) - \(\dfrac{1}{3}\)

Answer 1

a: \(\Leftrightarrow x\cdot\dfrac{8}{3}=\dfrac{119}{12}\)

=>x=119/32

b: \(\Leftrightarrow1-x=\dfrac{87}{128}\)

=>x=41/128

 

Answer 2

\(a,x.\dfrac{8}{3}=\dfrac{7}{2}+\dfrac{77}{12}\\ x.\dfrac{8}{3}=\dfrac{119}{12}\\ x=\dfrac{119}{12}:\dfrac{8}{3}\\ x=\dfrac{119}{32}\\ b,1-x=\dfrac{29}{12}:\dfrac{32}{9}\\ 1-x=\dfrac{87}{128}\\ x=\dfrac{41}{128}\\ c,\dfrac{16}{3}x-\dfrac{11}{4}=\dfrac{7}{2}.\dfrac{10}{8}-\dfrac{1}{3}\\ \dfrac{16}{3}x-\dfrac{11}{4}=\dfrac{35}{8}-\dfrac{1}{3}\\ \dfrac{16}{3}x-\dfrac{11}{4}=\dfrac{97}{24}\\ \dfrac{16}{3}x=\dfrac{163}{24}\\ x=\dfrac{163}{128}\)

Answer 3

a,\(x=\dfrac{119}{32}\)

b,\(x=\dfrac{41}{128}\)

c,\(x=\dfrac{163}{128}\)